A particle is projected vertically up from the top of a tower with velocity 10m/s it reaches the ground in 5 sec. find the distance travelled by particle.
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When the particle is projected vertically from the top of the tower, it takes the following time to reach maximum height.
Time to reach maximum height is :
T = u/g
U = the initial velocity
g = gravitational acceleration.
g = 9.8
U = 10m/s
T = 10/9.8 = 1.0204s
The time it takes to fall from maximum height to the ground is :
5 - 1.0204 = 3.9796 seconds
The initial velocity is 0 since at maximum height the velocity is zero.
S = ut + 0.5gt²
S = 0 + 0.5 × 9.8 × 3.9796²
S = 77.602
The distance travelled by the particle is thus 77.602m.
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