Question

A particle is projected vertically upward another particle b is projected at an angle of 45° both reach the same height ratio of initial kinetic energy of a to that of B is​

Answer 1

k. e=1/2mv^2 cos^2 90... eqn1

k. e'= 1/2mv^2cos^2 .45....eqn2

equate

ratio is 0