A particle is projected vertically upward from A with a speed of 50m/s and another is simultaneously from B, which is 200m vertically above A. They cross each other after what time?
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A particle is projected from point A vertically upwards with a speed of 50 m/s and another is dropped simultaneously from N which is 200m vertically above A. After how many minutes will they cross each other? S=50*t+1/2a*t^2 . S=1/2a*t^2 (since the particle is dropped so u=0).
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