A particle is projected vertically upward from ground eith velocity 10m/s find time taken by it to reach at the highest point
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Answered by
15
u=10m/s
v=0
a=g=-10m/s^2 as ball is thrown upside
2as=v^2-u^2
2×-10×s=0^2-10^2
s=-100/-20
s=5m
v=0
a=g=-10m/s^2 as ball is thrown upside
2as=v^2-u^2
2×-10×s=0^2-10^2
s=-100/-20
s=5m
Answered by
13
Answer:
You can find in either way but first one is much easier...
Hope it helps...✌️✌️✌️
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