Question

A particle is projected vertically upward returns back again to the point of projection after 6 seconds then height reached by the particle is_______​

Answer 1

Answer:

When time = 6 sec

V = 0 m/sec

And acceleration due to gravity = - 10 m/sec^2

Using the equation of motion..

V = u + a*t

0 =u -10 *6

So u = 60 m/sec

Now use the second equation of motion

To find height...

S = ut +1/2at^2

S = 60*6 - 1/2*10*36

By solving we get the height = 200 m