Question

A particle is projected vertically upward such that distance travelled by it in 5th second and 6th second are equal ,then distance travelled by it in 10th second will be

Answer 1

When a body is projected upwards it is acted upon by the gravitational force.

The distance it travels in the preceding second is always more than the distance it covers in the next second.

For these distances to be equal, the the object should reach the maximum height in the preceding second.

In our case the object reaches maximum height in the sixth second.

At maximum height the final velocity is 0.

Taking g = 9.8 we have :

V = u - gt

V = 0

0 = u - 9.8 × 6

U = 58.8

The initial velocity is thus :

= 58.8 m/s