Question

A particle is projected vertically upwards from a point a on the ground it takes time t1 to reach the point b but it still continues to move ok if it takes for the time to reach the ground from the point with and height of points from the ground is

Answer 1

Answer:

Explanation:

Sy = uy + 1/2 ay. t^2

When the particle reaches the ground , Sy = 0

Total time taken by the particle to reach the ground = t1 + t2

Therefore , 0 = uy (t1 + t2) - g/2 (t1 + t2)^2

0 = (t1 + t2) [uy - g/2 (t1 + t2)]

uy = g/2 (t1 + t2)

Let the height of the point B from the ground be H

H = g/2 (t1 + t2) t1 - 1/2g t1^2

=1/2g t1 (t1 + t2 - t1)

= 1/2g.t1. t2

Hope it helps!