Question

A particle is projected vertically upwards from a point a on the ground it takes T1 time to reach point B but it still continue to move up if it takes for the T2 time to reach the Ground from point B when height of point B from the ground is ​

Answer 1

Answer:

Time taken for the particle to reach highest point is t1+t22

(v=u−gt)

Therefore initial velocity=u=g(t1+t22)

Therefore heigh of B from ground is

h=ut+1/2at2

h=ut1−1/2gt12

=g(t1+t22)t1−1/2gt21

h=1/2gt1t2

Hope this helps u