Question

A particle is projected vertically upwards from ground with an initial speed of 57 m/s. If
acceleration due to gravity is taken Why be equal to 10 m/s2, then the displacement of the
particle in the sixth second of its motion will be

Answer 1

Explanation:

DATA:

Vi = 57m/s

acceleration due to gravity= 10m/s²

time = 6 sec

displacement = S= ???

SOLUTION:

S = Vit + 1/2 gt²

S = (57) (6) + 1/2 (-10) (6)²

since the particle is projected vertically upward so the acceleration due to gravity will be negative

S = 342 + (-180)

S = 342 - 180

S = 162 m

so the displacement of a particle in the sixth second of its motion will be 162 m.