A particle is projected vertically upwards from the ground with velocity 10 m/s. Find the time taken by it to reach at the highest point
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You can also ask the inverse: if you let a particle drop with zero initial speed, how long does it take until it reaches a velocity of 10 m/s?
v(t)=g⋅t+v0v(t)=g⋅t+v0
t=v(t)−v0gt=v(t)−v0g
Plug in v(t)=10msv(t)=10ms, v0=0msv0=0ms and g=9.81ms2g=9.81ms2 and you‘ll get t≈1.01937st≈1.01937s.
v(t)=g⋅t+v0v(t)=g⋅t+v0
t=v(t)−v0gt=v(t)−v0g
Plug in v(t)=10msv(t)=10ms, v0=0msv0=0ms and g=9.81ms2g=9.81ms2 and you‘ll get t≈1.01937st≈1.01937s.
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