A particle is projected vertically upwards. It attains a height ‘h’ when t= 2 seconds and again t= 10 seconds. The speed of the particle at the height h is (g = acceleration due to gravity at the place)
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11th
Physics
Motion in a Straight Line
Problems on Equation of Motion
A particle is projected ver...
PHYSICS
A particle is projected vertically upwards and it attains maximum height H. If the ratio of times to attain height h(h<H) is 1/3, then h equals
December 27, 2019avatar
Mano Suraj
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Total time taken to reach height H=t=
g
2H
Initial velocity=u=
2gH
Time to reach height h=t
1
=t/3=
3
1
g
2H
Now by second equation of motion
⇒h=ut
1
+0.5×(−g)(t
1
2
)
⇒h=
2gH
×
3
1
×
g
2H
−0.5×g×(
3
1
g
2H
)
2
⇒h=
3
2H
−
9
H
=
9
5H
⇒
H
h
=
9
5
Hence none of the options are correct
Explanation:
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