Question

A particle is projected vertically upwards with velocity 40m per sec .find displacement and distance travelled by particle

Answer 1

in going upward a = −gtime taken to react the top most point is tv =u −gtt = 4010t = 4 sdistance travelled in 4s1 = ut − 12gt2s1 = 40×4− 0.5 ×10×16 = 80 mafter 4 s body will start moving in downward directiontotal time is 6 sdistance travelled in 2 s in vertically downward direction :s2 = ut + 12gt2s2 = 0 +0.5×10×4 = 20 mTotal distance travelled is 80+20 = 100 mNet displacement is 80−20 = 60 m