Question

a particle is projected with a speed of 10m/s on a rough horizontal surface. If it retards at a rate of 2m/s^2 the speed of the particle after 6 seconds is?
1. -2m/s
2. 2m/s
3. zero
4. none of these​

Answer 1

Answer:

non of these

Explanation:

hagahahaha

Answer 2

Answer:

$\bold{initial \: velocity(u) \: = 10m {s}^{ - 2}}$

$\bold{acceleration(a) \: = 2 {m}^{ - 2}}$

$\bold{time(t) \: = 6s}$

$\bold{final \: velocity(v) \: = v}$

therefore,

$\bold{a \: = \: \frac{(v - u)}{t}}$

$\bold{2 \: = \: \frac{(v - 10)}{6}}$

$\bold{2 \times 6 \: = \: v - 10}$

$\bold{12 \: = \: v - 10}$

$\bold{12 + 10 \: = v}$

v = 22m/s²............

so,

the correct option is,

4. none of these....