Question

a particle is projected with a speed u at an angle theta to the horizontal find the radius of curvature at the highest point of its trajectory

Answer 1

HEYA ! !


Let the velocity of particle be u and angle with which it makes with horizontal is θ.The vertical component of the particle at the highest point is equal to zero.Considering only horizontal component,we get,
r=u2cos2θ2g

HOPE IT HELPS ✌
Regards.

Answer 2

Hello Friend..❤️❤️

The answer of u r question is..✌️✌️


Let,

Velocity of particle = U

Angle makes with horizontal = tita

We know that,

✔️✔️The vertical component of the particle at the highest point is equal to zero✔️✔️

So,

The answer is

=2cos2tita2g


Thank you..⭐️⭐️⭐️