A particle is projected with a speed V from a point O making an angle of 30° with the vertical. At the same instant, a second particle is thrown vertically upwards from a point A. The two particles reach H, the higest point on tge parabolic path of particle simulataneously. Then ratio V/v is
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Answer:
V/v = 2/√3
Explanation:
Let the speed of 1st particle be V
Height at highest point on parabolic path be H.
By formula:
H = V^2sin^2(60°)/2g
H= 3V^2/8g
Putting this value of H in
v = √2gH
V/v = 2/√3.
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