Question

A particle is projected with a velocity 200 m//s at an angle of 60^(@). At the highest point it explodes into three particle of equal masses. One goes vertically upward with a veloctiy 100m//s the second particle goes vertically downwards at same speed. What is the velocity of the third particle?

Answer 1

Answer:

300m/s

Explanation:

at highest point vt velocity will be zero while hz will be constant.

at that by conservation of linear momentum

MV = M/3 ×100 - M/3 ×100 + M/3 ×V

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