Question

A particle is projected with a velocity v (3i-j+2k) m/s and a constant acceleration acting on the particle is a=(-6i+2j-4k then the path of the projectile is- a) straight line b)parabola c) circle d)ellipse​

Answer 1

Hey brainly user

here is your answer

The answer is parabola

Reason : When a object is thrown into air with certain velocity and making an angle Φ with horizontal axis and at acceleration of the body is regarded as the projectle

» When a body is thrown up then due the gravitational pull there exits a force downwards and the body falls down

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Answer 2

Answer:

I think the answer will be (a) straight line because the particle provided continuous and constant acceleration,so the body moves to the straight line. the parabolic is when the particle provided acceleration due to gravity... it on does not work on particle because the weakest force is gravitational force and acceleration take the particle to some other way....

hope it helps....