A particle is projected with a velocity v, so that its range on a horizontal plane is twice the greatest height attained. If g is accelerated due to gravity, then its range is ; find
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H = R tan Ф / 4
R = 2 H
So tan Ф = 2
sin 2Ф = 2 * 2 / (1+2²) = 0.8
range = v² sin 2Ф / g = 0.8 v²/g
R = 2 H
So tan Ф = 2
sin 2Ф = 2 * 2 / (1+2²) = 0.8
range = v² sin 2Ф / g = 0.8 v²/g
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