Question

A particle is projected with an initial velocity of 200 m/s in a direction making an angle of 30' with the vertical. The horizontal distance covered by the particle in 3s is
1) 300 m 2) 150 m 3) 175 m 4) 125 m​

Answer 1

Hey Dear,

◆ Answer -

(1) s = 300 m

● Explaination -

# Given -

u = 200 m/s

θ = 90°-30° = 60°

t = 3 s

# Solution -

Horizontal velocity of the projectile is given as -

ux = u.cosθ

ux = 200 × cos60°

ux = 200 × 0.5

ux = 100 m/s

Distance covered in 3 s will thus be -

s = ux.t

s = 100 × 3

s = 300 m

Hence, distance covered by the particle in 3 s will be 300 m.

Thanks dear...

Answer 2

Answer:

the answer is 300 meters