Question

A particle is projected with speed 10 M per second at angle 60 with the horizontal then the time at which its speed become half of initial

Answer 1

hope this will help you.

Answer 2

uy = usinθ

= usin 60°

= 10 × √3/2

= 5√3 m/s

If the velocity becomes half of uy , then

uy/2 = 5√3/2

t = 2usinθ/2/ g

= 2 × 5√3/2/ 10

= √3/2 s