A particle is projected with speed 10 metre per second at angle 60 degree with the horizontal then the time after which its speed become half of initial
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Horizontal component remain equal at all pt= v cos theta. at any pt speed of ball is resultant of horizontal and vertical component.Vertical component at any pt is v sintheta- gt.
v and theta is known. Just create an eqn and solve.
1st get ur concepts clr. After that you will be able to solve maximum questions of projectile.
v and theta is known. Just create an eqn and solve.
1st get ur concepts clr. After that you will be able to solve maximum questions of projectile.
max20:
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