a particle is projected with speed 20m/s at an angle 30 degree with vertical the ratio of maximum height to horizontal range
Answers
Answered by
16
a particle is projected with 20 m/s at angle 30° with vertical or 60° with horizontal.
maximum height = u²sin²Φ/2g
where u is initial speed of projectile.Φ is angle of projection with horizontal.g is acceleration due to gravity.
maximum height = (20)² × sin²60°/2(10)
= 20 × 3/4 = 15m
horizontal range = u²sin2Φ/g
= (20)² × sin120°/10
= 40 × √3/2 = 20√3
hence, ratio of maximum height to horizontal range = 15/20√3 = √3/4
maximum height = u²sin²Φ/2g
where u is initial speed of projectile.Φ is angle of projection with horizontal.g is acceleration due to gravity.
maximum height = (20)² × sin²60°/2(10)
= 20 × 3/4 = 15m
horizontal range = u²sin2Φ/g
= (20)² × sin120°/10
= 40 × √3/2 = 20√3
hence, ratio of maximum height to horizontal range = 15/20√3 = √3/4
Similar questions