Question

A particle is projected with speed 20m/s at an angle 37 with the horizontal the velocity vector of the particle at t=1/2 s will be

Answer 1

Answer:

17.5 m/s  at 23.6°

Explanation:

particle is projected with speed 20m/s at an angle 37 with the horizontal

Horizontal speed = 20 Cos37 = 20 * 0.8 = 16 m/s

Vertical Speed = 20 Sin37 = 20 * 0.6 = 12 m/s

At T = 1/2 Sec  

Vertical Speed = 12 - (1/2)10   using V = U + at  a = -g = -10 m/s²

=> Vertical Speed =  7 m/s

Horizontal Speed = 16 m/s

Velocity at t = 1/2   is √7² + 16²  = 17.5 m/s

Angle = 23.6°