Question

A particle is projected with speed u at an angle theta with horizontal.The average velocity of the projectile between the instants it crosses the same level is (1)u cos (theta) (2)u sin(theta) (3)u cot(theta) (4)u tan(theta)

Answer 1

1)ucos(theta)
since the particle Is projected in the horizontal direction it is ucos(theta) if the gets projected in the vertical then it Is u sin(theta)

Answer 2

Answer: (1)u cos (theta)

Explanation:

The components of velocity are:

V x = u cos θ

V y = u sin θ

Average velocity is given by the ratio of displacement and total time taken.

In vertical direction, net displacement is zero as it is crossing the same level.

Thus, the average vertical velocity is zero.

In horizontal direction, there is no change in velocity. The horizontal velocity is constant and is given by:

V x = u cos θ

Thus, the net average velocity = u cos θ