Question

A particle is projected with speed v0 at
angle theta to the horizontal on an inclined
surface making an angle phi (phi< theta) to the
horizontal. Find the range of the projectile
along the inclined surface.​

Answer 1

Answer:

R={2Vo^2}/{g} x {sinФ cosФ(Ф +∅) / {cos^2Ф }

Explanation:

Let the particle strike the plane at end point so that R is the range of the projectile on inclined plane.

Here we are given that the initial speed of particle is  Vo

Angle of particle from incline surface = θ

Angle of incline surface from horizontal =Φ

The formula for range R given as

If particle is moving upward

R={2Vo^2}/{g} x {sinФ cosФ(Ф +∅) / {cos^2Ф }