Question

A particle is projected with velocity 20 m/s at an angle of 45° with horizontal. Find out the ſtake g=10mis)
(a) horizontal Range
(b) Maximum Height
(c) Time of flight
(d) For which angle is T maximum, Tmax = ?
(e) For which angle is R maximum , Rmax = ?​

Answer 1

Explanation:

(a) horizontal range= u^2 sin(2x)/g

=20^2sin(45×2)/10

=400/10

= 40m

(b)Hmax= u^2sin^2x/2g

=400xsin^2(45)/20

=20×1/2

= 10m

(c)time of flight= 2usinx/g

=2x20 sin45/10

=4x1/√2

=2√2 secs

hope it helps!!!