Question

A particle is projected with velocity of 10m/s at an angle of 15degree with horizontal. The horizontal range will be

Answer 1

Answer:

5 m

Explanation:

R=u2sin2theta/g

R=100*1/20

R=5m

Answer 2

Answer:

5 m

Explanation:

R = {u^2 sin 2 X 15}/g

R = 100 × 1/20

R = 5 m