Question

A particle is projected with velocity of (40underoot2) making an angle of 45° with the horizontal, the magnitude of velocity of the particle at t = 1 s after projection, will be 40 m/s 20root3m/s 20root5m/s 50 m/s

Answer 1

u=40iˆ+40jˆ

a=−10jˆ

t = 2s

(a) Apply v=u+at as a=constant

(b) Apply s=ut+12at2