Question

A particle is projected with velocity u at an angle θ with the vertical. Show that its path is parabolic. If the velocity of the projection of the particle is doubled, what is the percentage change in maximum height attained by projectile​

Answer 1

Thanks kindly please check the question ONCE

NICE QUESTION

Answer 2

Answer:

Correct option is

B

19.6m

times taken to reach P is 1s therefore

v2=u2+2aS

v2=u2cos2θ−2gh

let the distance from P to reach at the top be x

v2=u2+2as

0=u2cos2θ−2gh−2gx

x=2gu2cos2θ−h

time taken is v=u+at

0=ucosθ−g−gt

t=gucosθ−1

time taken to reach top from P is 1s

2g=ucosθ

maximum height H=2gu2cos2θ as the verical component is ucosθ

therefore H=2g(2g)2=2g=19.6m