A particle is projected with velocity v so that its range on a horizontal plane is twice the great height attend if g is acceleration due to gravity than its range is
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v²sin2Ф/g=2*v²sin²Ф/g
=> 2sinФcosФ=2sin²Ф(sin2Ф=2sinФcosФ)
=>sinФ=cosФ
=>Ф=45
Range=v²sin2Ф/g
butФ=45
v²sin90/g
=>v²/g is the range
Please mark it as the brainliest
=> 2sinФcosФ=2sin²Ф(sin2Ф=2sinФcosФ)
=>sinФ=cosФ
=>Ф=45
Range=v²sin2Ф/g
butФ=45
v²sin90/g
=>v²/g is the range
Please mark it as the brainliest
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