Question

A particle is pushed along a horizontal surface in such a way that it start with a velocity of 12 metre per second. Its velocity decreases at a rate of 0.5 metre per second square. find the time it wil take to come to rest.​

Answer 1

$\huge\underline\mathbb{Question??}$

▪A particle is pushed along a horizontal surface in such a way that it start with a velocity of 12 metre per second. Its velocity decreases at a rate of 0.5 metre per second square. find the time it wil take to come to rest.

$\huge\boxed{\fcolorbox{white}{pink}{Answer}}$

Given :-

☞ Initial velocity (u) =12 m/s.

☞Final velocity (v) =0

☞Acceleration (a) =-0.5m/s square.

Now, by using 1st equation of motion

☞ v=u+at

.☞0=12+(-0.5)×t

☞(0.5)×t=12

☞t=12×10/5

☞t =24 s.

Hence the required answer will be 24 second.

hope this answer helps you..

Answer 2

Answer:

it is 24 secs.-----

u=12m/s

a= -0.5m/s

v=0m/s

t=?

we know that,

                 v=u+at

so,    0=12+(-0.5)t

     -12= -0.5t

       t =-12/-0.5

       t=24 seconds