A particle is pushed along a horizontal surface in such a way that it starts with a velocity of 12m/s. It's velocity decreses at a uniform rate of 0.5m/s/s (1) find the time it will take to come to rest. (2) Find the distance covered by it before coming to rest?
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heya dear your answer is here
___________
u=12
v=0
a= -0.5
t=?
s=?
a=(v-u)/t
t=(v-u)/a
t=(0-12)/-0.5
t= 24sec
s= ut+(at^2)/2
s=12*24+(0.5* 24^2)/2
s =432m
___________
u=12
v=0
a= -0.5
t=?
s=?
a=(v-u)/t
t=(v-u)/a
t=(0-12)/-0.5
t= 24sec
s= ut+(at^2)/2
s=12*24+(0.5* 24^2)/2
s =432m
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