Question

A particle is released from rest from large height H. Assuming g is constant, find time taken to travel 1 last m.

Answer 1

A particle is released from rest from large height H. Assuming g is constant, find time taken to travel 1 last m.

A particle is released from rest from height h. so, time taken to reach the ground is given as , t(h) = √{2h/g} = √(2/g) √h

[ i.e., time is function of height. ]

if h is very large,

dt = √(2/g) 1/2√(h) × dh

⇒dt = dh/√(2gh)

here, dh = 1 m

so, dt = 1/√(2gh)

hence, time taken to travel one last metre is 1/√(2gh)

Answer 2

$\huge\bold\purple{Answer:-}$

A particle is released from rest from large height H. Assuming g is constant, find time taken to travel 1 last m.

A particle is released from rest from height h. so, time taken to reach the ground is given as , t(h) = √{2h/g} = √(2/g) √h

[ i.e., time is function of height. ]

if h is very large,

dt = √(2/g) 1/2√(h) × dh

⇒dt = dh/√(2gh)

here, dh = 1 m

so, dt = 1/√(2gh)

hence, time taken to travel one last metre is 1/√(2gh)