Question

A particle is revolving in a circle of radius 1m with an angular speed of 12rad/s. at t= 0

Answer 1

v = r * omega
v = 1*12
v = 12m/s

Answer 2

A particle is moving constantly and it is moved with angular acceleration and taking part in 4 rad/s^2.

The circular path should be measure and time t=0 and particle was at a rest position.

This must be identified with magnitudes of A and beginning to speed raise at ω = αt. v/r = 4t. v = 4tr.

Extraneous increasing speed = centripetal quickening. αr = a. 4r = v^2/r. 4r = (4tr)2/r. 4 = 16t^2. t = ½.