A particle is revolving in a circle of radius R with initial velocity u . Its starts retarding with constant retardation v²/4πR . The number of revolutions it makes in time 8πR/u is
Answers
Answer:2
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Explanation:
v²-u²=2as
0²-v²=-2as
v²=2as
a=v²/2s
S=v²/2a=v²×4πR/2v²
=2πR
v=u-at
0=v-v²t/4πR
t=4πR/v
time left for particle to move
=8πR/v-4πR/v
=4πR/v
s=ut+1/2at²
=1/2 at² (as u=0)
angle moved ∅=2πR/R
=2π
=One revolution
So, total number of rotation is 2
The total number of rotation is 2.
Explanation:
Given that,
Radius = R
Time
Retardation
We need to calculate the distance moved by the particle along circle before coming to rest
Using equation of motion
Here, u = 0
Put the value of a into the formula
We need to calculate the angle moved
Using formula of angle moved
Where, s = distance covered
r = radius
Put the value into the formula
Which is equal to one revolution
We need to calculate the time taken by particle stop
Using equation of motion
Put the value into the formula
Time left for the particle to move is
Put the value into the formula
We need to calculate the distance covered by the particle in this time
Using equation of motion
Put the value into the formula
We need to calculate the angle
Using formula of angle
Put the value into the formula
Which is equal to the one revolution
Hence, The total number of rotation is 2.
Learn more :
Topic : revolution
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