Question

A particle is revolving in a circular path of radius 2 m with constant angular speed 4 rad/s. The angular acceleration
of particle is
(1) Zero
(2) 8pie^2 rad/s2
(3) 16pie^2 rad/s2
(4) 128pie^2 rad/s2​

Answer 1

Answer:

Zero

Explanation:

At CONSTANT angular speed the angular acceleration is zero.

Answer 2

Answer:

A particle is revolving in a circular path of radius 2 m with a constant angular speed of 4 rad/s. The angular acceleration  of particle is zero

Explanation:

• The angular acceleration(a) is the change in angular velocity($w_{2} -w_{1}$) with time(t), which is

       $a=\frac{w_{2} -w_{1} }{t}$

From the question, we have

the radius of the path is $r=2m$

constant angular speed means it is not changing with time

the initial angular speed $w_{1}=4rad/s$

final angular speed  $w_{2}=4rad/s$

⇒$w_{2}-w_{1} =0$

therefore the angular acceleration $a=\frac{0}{t} =0$