Question

a particle is revolving in a circular path of radius 25m with constant angular speed 12 rev /min then the angular acceleration of particle is?

Answer 1

Answer: Zero

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Here we are asked a question from Rotational Kinematics.

We are asked Angular Acceleration of a particle, so we must first understand it.

Angular Acceleration is defined as the rate of change of angular velocity with respect to time.

In mathematical form, it is written as:

$\displaystyle \boxed{\alpha = \frac{\Delta \omega}{\Delta t}} \\ \\ \\ OR \\ \\ \\ \boxed{\vec{\alpha}=\frac{d\vec{\omega}}{dt}}$

Angular Acceleration is related to Tangential Acceleration as follows:

$\boxed{\vec{a_t}=r\vec{\alpha}}$

where r is the radius of the circular path.

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In the question, the particle is revolving in a circular path with a constant angular speed.

Constant Angular Speed implies that there is no change of Angular Speed with time.

So, $\Delta \omega = 0$

And from the formula of Angular Acceleration, we see that:

$\displaystyle \alpha = \frac{\Delta \omega}{\Delta t} = \frac{0}{\Delta t} = 0 \\ \\ \\ \implies \boxed{\boxed{\alpha=0}}$

Angular Acceleration becomes ZERO.

Answer 2

Answer:Answer:0

Explanation:

angular velocity constant दे रखी है।

speed constant है तो tangential acc तो 0 हो गई।

और

centripetal acc .=change in angular velocity divided by time taken ...

therefor Final -initial velocity /time

=0/time

=0...

..

.

.

waise question dekh kar mein bhi confuse ho gyi ki ye 12 rev /min kya hai. ..par fir doobara padha to pata chala ki kuch bhi ho .uski to jarrurat hi ni hia

Read more on Brainly.in - https://brainly.in/question/9127717#readmore

Explanation: