Question

A particle is revolving in a circular path of radius 2m with constant angular speed 4rad/s .the angular acceleration of particle is?

Answer 1

since angular velocity is constant, so zero will be the answer

Answer 2

The angular acceleration of particle is zero.

Explanation:

• We have a circular path whose radius is given as r = 2m
• Next we have the velocity of the particle moving in the  circular path ω or angular velocity = 4 rad/s
• To find out the acceleration that a particle is going through we have to see the rate of change of the velocity in circular path or angular velocity, let it be “a”
• Now, since we are given that the particle is moving in a circular path or is revolving on a circular path with a constant velocity 4 Radian per second.

• Hence, there is no fluctuation in the velocity at any moment of time hence the rate of change of velocity would be zero which gives us that acceleration is zero.

To know more:

A particle is moving with the constant angular acceleration of 4 rad/s2 in a circular path. At time t = 0, the particle was at rest. Find the time at which the magnitudes of centripetal acceleration and tangential acceleration are equal.

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