Question

A particle is shot up from earth surface with velo 1km/s. Find greatest height

Answer 1

ENERGY CONSERVATION::

mgh = ½mv²

gh = ½v²

h = ½v²/g

I assume g=10 m/s²

so , h = ½v²/10

h = 50,000 m

h = 50km from surface of earth

HOPE IT HELPS...

Answer 2

Answer :-

Step by step explanation :-

From law of Energy Conservation we know that

$mgh = \frac{1}{2} m {v}^{2} \\ \\ gh = \frac{1}{2} {v}^{2}$

Here we have velocity is 1km/s = 1000m/s.

Put values

$h = \frac{ \frac{1}{2} {v}^{2} }{g} \\ \\ h = \frac{ \frac{1}{2} \times 1000 \times 1000 }{9.8} \\ \\ h = 51000m \\ \\ h = 51km$

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