Physics, asked by saptarshimampi, 6 months ago

 A particle is simultaneously subjected to two S.H.M.in the same direction each of frequency 5Hz .If the amplitudes are 0.005m and 0.002m respectively and phase difference between them is 45^(0) find the amplitude of resultant displacement and its phase relative to the first component.Write down the expression for the resultant displacement as a function of time. ​

Answers

Answered by himanshubainiwal68
0

Answer:

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Explanation:

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