Question

A particle is starting from rest and moving with a constant acceleration 'a'. The ratio of the distance
travelled in the first, second, third and fourth seconds is
a)1:4:9:16
b) 1:1:1:3
c) 1:2:3:4
d) 1:3.5:7
a) 1:4:9:16​

Answer 1

Answer:

answer is 1:3:5:7

Explanation:

u can calculate distance travelled in a particular second by subtracting total distance travelled up to that second - distance travelled up to previous second

Answer 2

Answer:

Option A

Explanation:

u=0 given

$s=ut+½at²$

so apply,

S= 0×t+½a(1)²=1/2a

Similarly,

S1:S2:S3:............= 1²:2²:3²:4²:..............

=1:4:9:16:........

only consider ratios of S1:S2:S3:S4 =1:4:9:16

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