Physics, asked by ganesamokkapati, 4 months ago

A particle is starting from rest and moving with a constant acceleration 'a'. The ratio of the distano
travelled in the first, second, third and fourth seconds is
[ 1
a) 1:4:9:16
b) 1:1:1:3
c) 1:2:3:4
d) 1:3:5:7​

Answers

Answered by siddharthchatu82
1

Answer:

a particle starting from rest now you call to zero starting from rest I think your answer is bi C1 is to 2 is to 3 is to 4

Answered by dragonsragespell
2

Answer:

d, 1:3:5:7

Explanation:

obvious stuff

just put n= 1 , 2 , 3s ....

in

s of n th second= u+ 0.5 a ( 2n-1)

to get distance at n th sec

ratio of velocities is 1:2:3:4

ratios of total distance covered at time t is 1 : 4 : 9 : 16

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