Question

A particle is starting from rest and moving with a constant acceleration a, the ratio of the distan travelled in time intervals t 1, 2, 3, and 4 seconds respectively is​

Answer 1

Answer:

Let s  

n

​  

 be the distance travelled in nth sec

sn=u+  

2

a

​  

(2n−1)

u=0 so

s=  

2

a

​  

(2n−1)

s  

1

​  

:s  

3

​  

:s  

5

​  

=(2×1−1):(2×3−1):(2×5−1)

s  

1

​  

:s  

3

​  

:s  

5

​  

=1:5:9

Explanation: