A particle is starting from rest moves with acceleration of a = 2t + 1, where a is in m/s2 and t is in second. the velocity of particle at t = 2 s is
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Answered by
1
hi friend this answer will
help you a lot in strengthening your concepts in laws of motion
u=0{starting from rest}
from Newton's first equation of motion
we know that v=u+at
since u=0
v= at
v={2t+1}t
v={2×2+1}×2 {t=2s}
v=8+2=10metre per second
help you a lot in strengthening your concepts in laws of motion
u=0{starting from rest}
from Newton's first equation of motion
we know that v=u+at
since u=0
v= at
v={2t+1}t
v={2×2+1}×2 {t=2s}
v=8+2=10metre per second
Answered by
0
hi friend
here's your answer looking for
according to your question if T = 2sec
then,
a= 2t+1
a = 2(2) + 1
a= 5 m/s^2
so, we get the a = 5m/s^2
if you are asking about final velocity then,
v = u + at
v = 0 + 5(2)
v= 10 m/ s
hope it's helpful to you
From brainly star Amaytripathi19
here's your answer looking for
according to your question if T = 2sec
then,
a= 2t+1
a = 2(2) + 1
a= 5 m/s^2
so, we get the a = 5m/s^2
if you are asking about final velocity then,
v = u + at
v = 0 + 5(2)
v= 10 m/ s
hope it's helpful to you
From brainly star Amaytripathi19
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