A particle is taken to a height of 2R, above the
earth's surface, where R is the radius of the earth.
Ifit is dropped from this height, what would be its
acceleration?
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Answer:
we know that
Re=radius of earth
ge=gravitation force of earth
gh=(Re/ Re+h)²ge
gh=(6400000/6400000×2)²9.8m/s²
gh=(1/2)²9.8m/s²
gh=1/4×9.8m/s²
gh=2.45m/s²
Hence,the acceleration is 2.45m/s²
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