Question

A particle is taken to height R above the surface of earth, where R is the radius of earth. Find the acceleration due to gravity

Answer 1

Answer:

Explanation:The particle which is taken to a height r more than earth's surface and when r is the radius of earth. The acceleration due to gravity will be same as experienced by the particle on the earth's surface. As the Gravitation Law put forth is uniform for the whole of the universe.

Answer 2

Acceleration due to gravity will become one fourth to the acceleration due to gravity on the surface of earth that is 1/4 times g

Explanation:

• Acceleration due to gravity is the gravitational force or simple acceleration which a free falling body will experience when coming towards the surface of earth. Its value is constant on the surface of earth but changes as we move the body above or below the surface of earth

It is given as g = $\frac{GM}{R^{2} }$    ..........................(1)

where, G= gravitational force

M = mass of Earth

R = Radius of Earth

When the particle is raised to height 'R' above the surface of earth

Then total distance from the center of earth will become R₁ = R+R = 2 R

So the acceleration due to gravity will be

=> g ' = $\frac{GM}{R_{1} ^{2} }$

=> g ' = $\frac{GM}{(2R)^{2} }$

=> g ' = $\frac{GM}{4R ^{2} }$

=> g' = $\frac{g}{4}$         ( from equation (1))

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