Question

A particle is thrown at an angle with speed vo with horizontal. After sometime particle moves with speed v at an angle ß with horizontal. The correct relation between vo and v is? ​

Answer 1

Given :-

• A particle is thrown at an angle θ with speed v₀ with horizontal. After sometime particle moves with speed v at an angle β with horizontal. The correct relation between v₀ and v is?

Solution :-

• Here, it is given that the particle is thrown at an angle v₀ at an angle θ and it moves with a speed v at angle β with horizontal after sometime
• As we know, during the whole journey of the projectile, the horzontal acceleration is zero so the horizontal velocity(vcosθ) is same.
• So we can equate the horizontal velocities at both the points.

       ⇒ v₀cosθ = vcosβ

       → So, that is the relation between v₀ and v

∴ The relation between v₀ and v is v₀cosθ = vcosβ

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→Sathvik :)