Question

A particle is thrown from a stationary platform with velocity v at an angle of 60° with the
th velocity v at an angle of 60° with the horizontal.
The range obtained is R. If the platform moves horizontally in the direction of target with Velochy
the range will increase to :​

Answer 1

Answer:

Range will increase to 3R

Explanation:

A particle is thrown from a stationary platform with velocity v at an angle of 60° with the

th velocity v at an angle of 60° with the horizontal.

The range obtained is R. If the platform moves horizontally in the direction of target with Velochy

the range will increase to :​

Horizontal Velocity = VCos60 = V/2

Vertical Velocity = VSin60 = V√3/2

Using V = U + aT

Time to reach max height =  V√3/2g

Time for Range = 2 * Time to reach max height  =  V√3/g

Range = R =  (V/2)*V√3/g

=> R = V²√3/2g

if Platform was moving with Velocity V

Then Horizontal Velocity = V + V/2 = 3V/2

Then Range = (3V/2)*V√3/g  = 3 *V²√3/2g = 3R

Range will increase to 3R