Question

A particle is thrown horizontally from a tower of height H .particle crosses horizontal line passing through mid point at a distance equal to height of tower (foot of the tower is taken as origin) .find initial velocity of particle.

Answer 1

Answer:

Time to reach the maximum height  

t  

1 = g

u

​  

 

If t  

2

​  

 be the time taken no hit the ground

−H=ut  

2

​  

−  

2

1

​  

gt  

2

2

​  

 

But t  

2

​  

=nt  

1

​  

 (given)

⇒−H=u  

g

nu

​  

−  

2

1

​  

g  

g  

2

 

n  

2

u  

2

 

​  

 

⇒2gH=nu  

2

(n−2)

Explanation: