A particle is thrown or projected with velocity 10m per sec in upward direction .so for this condition find a-t,v-t,. graph for total time of motion.
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Final Answer : Graph 1 : V-t Graph
Graph 2 : a - t graph
Convention :
Upward Direction : Positive
Downward Direction : Negative
Steps:
1) Initial, velocity u = 10 m/s
Due to acceleration due to gravity, \ = -10m/s^2
Velocity will decrease up-to 0 and reaches maximum height.
Then, it comes down ward starting from u =0 to v = -10m/s when it reaches ground.
Time taken to reach the ground , t = 2u/g =2s
Hence, Straight line graph as shown in Graph 1 .
2) Acceleration will always constant with value :
-10m/s^2 throughout the motion.
Hence, Graph will be as shown in Graph : 2 .
Graph 2 : a - t graph
Convention :
Upward Direction : Positive
Downward Direction : Negative
Steps:
1) Initial, velocity u = 10 m/s
Due to acceleration due to gravity, \ = -10m/s^2
Velocity will decrease up-to 0 and reaches maximum height.
Then, it comes down ward starting from u =0 to v = -10m/s when it reaches ground.
Time taken to reach the ground , t = 2u/g =2s
Hence, Straight line graph as shown in Graph 1 .
2) Acceleration will always constant with value :
-10m/s^2 throughout the motion.
Hence, Graph will be as shown in Graph : 2 .
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